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Byju's Answer
Standard XI
Statistics
Quartile Deviation
calculate the...
Question
calculate the mean deviation about mean of the set of first n natural numbers when n is an odd natural number
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Solution
First
find
the
sum
of
first
n
natural
numbers
where
n
is
an
odd
natural
number
.
Note
that
,
1
+
2
+
3
=
6
=
3
×
2
=
3
×
4
2
=
3
×
3
+
1
2
1
+
2
+
3
+
4
+
5
=
15
=
5
×
3
=
5
×
6
2
=
5
×
5
+
1
2
1
+
2
+
3
+
4
+
5
+
6
+
7
=
28
=
7
×
4
=
7
×
8
2
=
7
×
7
+
1
2
⋮
So
the
sum
of
first
n
natural
numbers
where
n
is
an
odd
natural
number
is
,
n
n
+
1
2
So
the
mean
of
the
first
n
natural
numbers
when
n
is
an
odd
natural
number
is
,
x
=
1
n
×
n
n
+
1
2
=
n
+
1
2
The
mean
deviation
about
mean
of
the
mean
of
first
n
natural
numbers
when
n
is
an
odd
natural
number
is
,
mean
deviation
=
∑
n
x
i
-
x
n
=
1
n
1
-
n
2
+
2
-
n
2
+
1
+
⋯
+
n
-
n
+
1
2
=
2
n
n
-
1
2
n
-
1
2
+
1
2
=
2
n
n
-
1
n
+
1
8
=
n
2
-
1
4
n
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