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Question

Calculate the mean deviation about the median of the following frequency distribution :

xi57911131517fi246810128

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Solution

xifiCumulative frequency|di|=|xi13|fi|di|5228167466249612424118202161310300015124222417850432N=fi=50ni=1fi|di|=136

Here,

N2=502=25

The cumulative frequency just greater than 25 is 30 and the corresponding value of x is 13.

Median, M = 13

M.D.=1Nni=fi|di|

=150×136=2.72


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