Calculate the mean deviation about the median of the following frequency distribution :
xi57911131517fi246810128
xifiCumulative frequency|di|=|xi−13|fi|di|5228167466249612424118202161310300015124222417850432N=∑fi=50∑ni=1fi|di|=136
Here,
N2=502=25
The cumulative frequency just greater than 25 is 30 and the corresponding value of x is 13.
∴ Median, M = 13
M.D.=1N∑ni=fi|di|
=150×136=2.72