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Question

Calculate the mean deviation about the median of the following observations:
(i) 3011, 2780, 3020, 2354, 3541, 4150, 5000
(ii) 38, 70, 48, 34, 42, 55, 63, 46, 54, 44
(iii) 34, 66, 30, 38, 44, 50, 40, 60, 42, 51
(iv) 22, 24, 30, 27, 29, 31, 25, 28, 41, 42
(v) 38, 70, 48, 34, 63, 42, 55, 44, 53, 47

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Solution

Formula used for mean deviation:
MD=1ni=1ndiHere, di=xi-M
M = Median

i) Arranging the data in ascending order:
2354, 2780, 3011, 3020, 3541, 4150, 5000

Here, median (M)=3020 and n = 7.
xi di = xi - 3020
3011 9
2780 240
3020 0
2354 666
3541 521
4150 1130
5000 1980
Total 4546

MD=1ni=1ndi

MD=17×4546=649.42

ii) Arranging the data in ascending order:
34, 38, 42, 44, 46, 48, 54, 55, 63, 70

Here, n is equal to 10.
Median is the arithmetic mean of the fifth and the sixth observation.

Median, M = 46+482 = 47
xi di = xi-M
38 9
70 23
48 1
34 13
42 5
55 8
63 16
46 1
54 7
44 3
Total 86

MD=110×86=8.6

iii) Arranging the data in ascending order:
30, 34, 38, 40, 42, 44, 50, 51, 60, 66

Here,
n=10
Also, median is the AM of the fifth and the sixth observation.

Median, M = 42+442 = 43
xi di = xi-M
34 9
66 23
30 13
38 5
44 1
50 7
40 3
60 17
42 1
51 8
Total 87

MD=110×87=8.7

iv) Arranging the data in ascending order.
22, 24, 25, 27, 28, 29, 30, 31, 41, 42

Here, n=10.
Also, median is the AM of the fifth and the sixth observation.

Median, M = 28+292 = 28.5
xi di = xi-M
22 6.5
24 4.5
30 1.5
27 1.5
29 0.5
31 2.5
25 3.5
28 0.5
41 12.5
41 13.5
Total 47

MD=110×47=4.7

v) Arranging the data in ascending order:
34, 38, 42, 44, 47, 48, 53, 55, 63, 70

Here, n=10.
Also, median is the AM of the fifth and the sixth observation.

Median, M = 47+482 = 47.5
xi di = xi-M
38 9.5
70 22.5
48 0.5
34 13.5
63 15.5
42 5.5
55 7.5
44 3.5
53 5.5
47 0.5
Total 84

MD=110×84=8.4

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