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Question

Calculate the mean for the following frequency distribution using direct method.

Class010102020303040405050606070fi68202515104


A
32.4
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B
34.2
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C
34.6
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D
36.4
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Solution

The correct option is B 34.2
First we find out the class marks.

Using class marks=lower limit+upper limit2

For the first class interval, class mark (xi)=0+102=5

Similarly, class marks for other classes can be calculated.
Class010102020303040405050606070xi5152535455565fi68202515104fi=88xifi30120500875675550260fixi=3010


Mean=fixifi

=301088

=34.2

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