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Question

Calculate the mean deviation about mean for the following data.

ClassFrequency0−10016100−20011200−3007300−40010400−5006

A
108.24
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B
110.48
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C
126.64
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D
132.9
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Solution

The correct option is C 126.64
ClassXFFX01005016800100201501116502030250717503040350103500405045062700F=50FX=10400

Mean=FXF=1040050=208

Deviations from the mean are tabulated below

X (class midpoint)FD=|X¯x|FD50161582528150115863825074229435010142142045062421452 F=50FD=6332

M.D(¯x)=633250=126.64

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