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Question

Calculate the mean of the following data by all three methods, and compare the results.

Class IntervalFrequency11011081101209120130111301401214015010 [4 MARKS]


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Solution

Concept: 1 Mark
Application: 1 Mark each

Class Intervalxififixi100110105884011012011591035120130125111375130140135121620140150145101450

fi=50 fixi=6320

Mean =632050=126.4

Assumed mean method:

Let assumed mean=125

Class intervalxifidifidi10011010582016011012011591090120130125110013014013512101201401501451020200

fi=50fidi=70

Mean =125+7050=126.4

Step-deviation method:

Let assumed mean = 125

Class size = 10

Class Intervalxifidiuifiui100110105820216110120115910191201301251100013014013512101121401501451020220

fi=50 fiui=7

Mean =125+(750×10)=126.4

The mean in all the three methods is equal to 126.4


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