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Question

Calculate the mean of the following distribution: [4 MARKS]
Class IntervalFrequency010810205203012304035405024506016

 


Solution

Formula: 2 Marks
Solution: 2 Marks

ClassFrequencyClassui=xiAhfiuiInterval(fi)markxi01088324102051521020301225112304035A(35)004050244512450601655232fi=100fiui=10
From the table, A = 35 and h = 10
Mean (¯x)=A+(fiuifi×h)
=35+(10100×10)=35+1=36


 

Mathematics

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