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Question
Calculate the median for the following frequency distribution.
Class0−1010−2020−3030−4040−5050−6060−70fi68202515104
Calculate the median for the following frequency distribution.
Class0−1010−2020−3030−4040−5050−6060−70fi68202515104
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Solution
The correct option is A 34
Class Interval0−1010−2020−3030−4040−5050−6060−70Frequency (fi)68202515104Cumulative Frequency6143459748488
In the above distribution the total number of observations is 88. Hence, n = 88.
n2=44.
The cumulative frequency that is greater than 44 but closest to 44 is 59. The class corresponding to this frequency is 30-40. This is the median class.
Using Median = l+(n2−cff)×h
Where l is lower class limit of median class.
n is the total number of observations.
cf is the cumulative frequency of the class preceding the median class.
f is the frequency of the median class and h is the class size.
⟹Median=30+44−3425×10
∴Median=34
Class Interval0−1010−2020−3030−4040−5050−6060−70Frequency (fi)68202515104Cumulative Frequency6143459748488
In the above distribution the total number of observations is 88. Hence, n = 88.
n2=44.
The cumulative frequency that is greater than 44 but closest to 44 is 59. The class corresponding to this frequency is 30-40. This is the median class.
Using Median = l+(n2−cff)×h
Where l is lower class limit of median class.
n is the total number of observations.
cf is the cumulative frequency of the class preceding the median class.
f is the frequency of the median class and h is the class size.
⟹Median=30+44−3425×10
∴Median=34
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