We prepare the cumulative frequency table, as shown:
Height | Frequency
(f) |
Cumulative frequency |
137.5 | 6 | 6 |
142.5 | 10 | 16 |
147.5 | 18 | 34 |
152.5 | 22 | 56 |
157.5 | 20 | 76 |
162.5 | 15 | 91 |
167.5 | 6 | 97 |
172.5 | 3 | 100 |
N=Σf=100 |
Here N= 100 (which is even )
⇒N/2=50
and also N/2+1 = 51
The median will lie between 50th
and the 51th observation but from the table we can see both the 50th and 51th observation corresponding to 152.5 in column of height
Thus the median height of the given data is 152.5 cm.