wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Calculate the median from the following data:
Marks below:1020304050607080
No. of students1535608496127198250

Open in App
Solution


Marks (x) No. of students (f) C.F.
0-101515
10-202035
20-302560
30-402484
40-501296
50-6031127
60-7071198
70-8052250
N = 250
As, N=250N2=2502=125

As 127 is just greater than 125, therefore median class is 5060.

Median=l+N2+Cf×h

Here, l=lower limit of median class =50

C=C.F. of the class preceding the median class =96

h= higher limit - lower limit =6050=10

f= frequency of median class =31

median=50+1259631×10=50+9.35=59.35

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Median
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon