Question

Calculate the minimum and maximum number of electrons which may have magnetic quantum number, $m=+1$ and spin quantum number, $s=-\frac{1}{2}$ in Chromium (Cr):

• A. $0,1$
• B. $1,2$
• C. $4,6$
• D. $2,3$

Answer 1

The correct option is D $2,3$

Out of 6 electrons in $2p$ and $3p$ must have an electron with $m=+1$ and $s=-\frac{1}{2}$ but in $3d-$ subshell an orbit having $m=+1$ may have spin quantum no. $-\frac{1}{2}$ or $+\frac{1}{2}$.
Therefore, minimum and maximum possible values are $2$ and $3$ respectively.