Calculate the mode for the following data $:$
Distance(km) $11$ $21$ $31$ $41$ $51$
Number of persons $4$ $6$ $10$ $20$ $18$

41

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31

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21

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11

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Solution

The correct option is D $41$
Mode for the discrete series is the variable which has the highest frequency.
From the given distribution table, the highest frequency is $20$ which is associated with the variable $41$
Therefore, the mode is $41$

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Similar questions

Q. What is the median class for the following data given below?

Distance(km)	$1 - 11$	$11 - 21$	$21 - 31$	$31 - 41$	$41 - 51$
Number of persons	$4$	$6$	$10$	$12$	$18$

Q. Find the mean of the following data

Marks	1 - 10	11 - 20	21 30	31 - 40	41 -50	51 - 60	61 - 70
No. of student	6	5	8	15	7	6	3

Class Interval	Frequency
$1 - 5$	$3$
$6 - 10$	$8$
$11 - 15$	$13$
$16 - 20$	$18$
$21 - 25$	$28$
$26 - 30$	$20$
$31 - 35$	$13$
$36 - 40$	$8$
$41 - 45$	$6$
$46 - 50$	$4$

Compute the mode of the given data.

Draw a frequency polygon for the following frequency distribution:
$\begin{matrix} Class interval & 1 - 10 & 11 - 20 & 21 - 30 & 31 - 40 & 41 - 50 & 51 - 60 Frequency & 8 & 3 & 6 & 12 & 2 & 7 \end{matrix}$

1 \frac{1}{3} + 2 \frac{1}{4} + 3 \frac{1}{6} + 4 \frac{1}{12} + . . . + 19 \frac{2}{3}

is equal to

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Distance(km)	$11$	$21$	$31$	$41$	$51$
Number of persons	$4$	$6$	$10$	$20$	$18$

Calculate the mode for the following data:Distance(km)1121314151Number of persons46102018

The correct option is D 41Mode for the discrete series is the variable which has the highest frequency.From the given distribution table, the highest frequency is 20 which is associated with the variable 41Therefore, the mode is 41

Calculate the mode for the following data $:$
Distance(km) $11$ $21$ $31$ $41$ $51$
Number of persons $4$ $6$ $10$ $20$ $18$

The correct option is D $41$
Mode for the discrete series is the variable which has the highest frequency.
From the given distribution table, the highest frequency is $20$ which is associated with the variable $41$
Therefore, the mode is $41$