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Question

Calculate the molality of a 20% CaCO3 solution (by mass). The density of the solution is 1.2 g/mL.

A
1.25 m
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B
2.50 m
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C
2.08 m
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D
1.52 m
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Solution

The correct option is B 2.50 m
Let the mass of the solution be 100 g.
Mass of CaCO3
=20 g
Mass of water = 80 g
Moles of CaCO3
=given massMolar mass=20100=0.2
Molality=moles of soluteweight of solvent (g)×1000=0.280×1000

Molality=2.5 m

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