Question

Calculate the molality of the solution containing 3g glucose dissolved in 30g of water.

[Molar mass of glucose = 180]

• A. 0.50 m
• B. 0.56 m
• C. 0.091 m
• D. 0.05 m

Answer 1

The correct option is B 0.56 m

Moles of glucose $=\frac{3}{180}=\frac{1}{60}$ $moles$

$Molality=\frac{Molesofsolute}{Massofsolvent\left(Kg\right)}=\frac{1\times 1000}{60\times 30}=\frac{5}{9}=0.56$ $m$

Hence, option $B$ is correct.