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Ideal Gas Equation

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Question

Calculate the molar mass of oxygen. If 6.4 gram of oxygen occupies volume of 4.8 dm $^{3}$ .

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Solution

mass of oxygen = 6.4 g
Volume = 4.8 dm
molar mass = ?
Let molar mass be M
$\frac{4.8}{22.4} = \frac{6.4}{2 x}$
$x = \frac{6.4 \times 22.4}{4.8 \times 2}$
$x \sim 15 g$

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