Calculate the molar ratio in which the following two substances would react?
$B a_{3} (P O_{4})_{2}$ and $A l C l_{3}$

2:1

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1:2

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3:1

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1:3

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Solution

The correct option is B 1:2
n-factor of $B a_{3} (P O_{4})_{2} = 3 (+ 2) = 6 - n_{1}$
While n-factor of $A l C l_{3} = 1 (+ 3) = 3 = n_{2}$
$\frac{n_{1}}{n_{2}} = \frac{6}{3}$ If $\frac{n_{1}}{n_{2}} = \frac{x}{y}$
Molar ratio $= \frac{y}{x}$ (inverse of equivalent ratio)
$∴$ Molar ratio in which $B a_{3} (P O_{4})_{2}$ and $A l C l_{3}$ will react = 3 : 6 = 1 : 2

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