Question

Calculate the molarity of 9.8% solution of ${\text{H}}_{\text{2}}\text{S}{\text{O}}_{\text{4}}$ if the density of the solution is 1.02 gmL${}^{-1}$.

Answer 1

Given, $9.8$ $gm$ $H_{2}S{O}_4$ is present in $100$ $mL$ solution. ($9.8\%$ $H_{2}S{O}_4$ solution $W/Volume$)

Moles of $H_{2}S{O}_4=\frac{9.8}{98}=0.1$

$Molarity=\frac{Molesofsolute}{V\left(litres\right)}=\frac{0.1\times 1000}{100}=1$ $Molar$