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Standard XII

Chemistry

Molarity

Calculate the...

Question

Calculate the molarity of a solution of 100 mL of 10 N $H_{2} S O_{4}$ which is diluted to 800 mL.

\frac{16}{10}

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\frac{8}{10}

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\frac{10}{8}

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\frac{10}{12}

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\frac{5}{8}

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Solution

The correct option is E $\frac{5}{8}$ M
Molarity of 10 N $H_{2} S O_{4} = \frac{normality}{2} = \frac{10}{2} = 5$ M
$M_{1} V_{1} = M_{2} V_{2}$
$M_{1} = 5 M$
$V_{1} = 100$ mL
$M_{2} =$ ??
$V_{2} = 800$ mL
$5 \times 100 = M_{2} \times 800$
$M_{2} = \frac{5}{8}$ M

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Calculate the molarity of a solution of 100 mL of 10 N H2SO4 which is diluted to 800 mL.

The correct option is E 58 MMolarity of 10 N H2SO4=normality2=102=5 MM1V1=M2V2M1=5MV1=100 mLM2= ??V2=800mL5×100=M2×800M2=58 M

Calculate the molarity of a solution of 100 mL of 10 N $H_{2} S O_{4}$ which is diluted to 800 mL.

The correct option is E $\frac{5}{8}$ M
Molarity of 10 N $H_{2} S O_{4} = \frac{normality}{2} = \frac{10}{2} = 5$ M
$M_{1} V_{1} = M_{2} V_{2}$
$M_{1} = 5 M$
$V_{1} = 100$ mL
$M_{2} =$ ??
$V_{2} = 800$ mL
$5 \times 100 = M_{2} \times 800$
$M_{2} = \frac{5}{8}$ M