Calculate the molarity of pure water. $(d = 1 g / m L)$

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Solution

Consider 1000 mL of water.
Mass of 1000 mL of water $= 1000 \times 1 = 1000 g$
No. of moles of water $= \frac{1000}{18} = 55.5$
Molarity $= \frac{N o . o f m o l e s o f w a t e r}{V o l u m e i n l i t r e}$
$= \frac{55.5}{1} = 55.5 M$

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