Calculate the mole fraction of benzene in solution containing $30$ % by mass in $C C l_{4}$ ?

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Solution

Let the mass of solution be $100 g m$

Mass of Benzene $= 30 g m$

Mass of $C C l_{4} = 70 g m$

Moles of Benzene $= \frac{30}{78} = 0.385$

Moles of $C C l_{4} = \frac{70}{154} = 0.45 m o l e s$

Mole fraction (Benzene) $= \frac{0.385}{0.385 + 0.45} = 0.461$

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