Calculate the mole fraction of ethanol in a sample of spirit containing 92+ ethanol by mass.

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Solution

$M a s s % o f e t h a n o l i s 92 % W a t e r i s 8 % M o l e s o f e t h a n o l = \frac{M a s s o f t h e g i v e n s u b s t a n c e i n g}{M o l a r m a s s o f e t h a n o l} = \frac{92}{46} = 2 M o l e s o f w a t e r = \frac{8}{18} = 0.444 M o l e f r a c t i o n o f e t h a n o l = \frac{M o l e s o f e t h a n o l}{M o l e s o f e t h a n o l + m o l e s o f w a t e r} = \frac{2}{2 + 0.444} = \frac{2}{2.444} = 0.818$

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