Calculate the mole fraction of ethylene glycol and water in a solution containing 20% of C₂H₆O₂by mass.

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Solution

20% of ethylene glycol is present in 100% soln. that means, 20 gm of ethylene glycol is present in 100 gm of glycol soln. Therfore, the moles of ethylene glycol = 20/62
= 0.322 mol.
moles of water
=(100 – 20)/18 =80/18
= 4.44 moles.
Mole fraction for ethylene glycol = 0.322/(0.322 + 4.44) =0.06761

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