Question

Calculate the mole fraction of $N_2$ gas in a mixture of $N_2$ and $O_2$. If the partial pressure of $O_2$ is 63 cm of Hg and the total pressure of the mixture is 90 cm of Hg.

Answer 1

Pressure of $N{O}_2\to 90-63$
= 27 cm of Hg
76 cm of $Hg\to 1atm$
27 cm of $Hg\to \frac{27}{76}cm$
$\frac{P_{N}2}{P_{Total}}$= Male fraction
Male fraction $N_2=\frac{\frac{27}{76}}{\frac{90}{76}}=\frac{27}{90}=\frac{3}{10}=0.3$