Calculate the mole fraction of toluene in the vapour pressure which in equilibrium with the solution of benzene and toluene having a mole fraction of toluene 0.5 the vapour pressure of pure benzene is 119 and that of toluene is 37 tour at the same temperature

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Q. Vapour pressure of pure benzene is

119 torr

and of toluene is

37.0 torr

at the same temperature. Then mole fraction of toluene in vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene

0.50,

will be:

Q. Calculate the mole fraction of toluene in the vapor phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of 0.5 (The vapor pressure of pure Benzene is 119 torr and that of toluene is 37 torr at the same temperature:

Q. Calculate the mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene 0.50. The vapour pressure of pure benzene is 119 torr; that of toluene is 37 torr at the same temperature. ( If the answer is

x

, then write

x \times 10^{- 3}

)(rounding off to 3 digits)

Q. Benzene and toluene form an ideal solution. Vapour Pressure of pure benzene is 100 torr while that of pure toluene is 50 torr. If mole fraction of benzene in liquid phase is

\frac{1}{3}

, calculate the mole fraction of benzene in vapour phase.

The vapour pressure of a benzene – toluene binary solution at certain temperature is given by $P = 450 - 100 X_{T}$ .
Where $X_{T}$ is the mole fraction of toluene. Find the vapour pressures of Benzene and Toluene in pure state.

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