calculate the mole fracton of benzene ina solution containing 30% by mass of it in carbon tetrachloride
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Solution
Let the total mass of the solution be 100 g and the mass of benzene be 30 g. ∴ Mass of carbon tetrachloride = (100 - 30)g = 70 g Molar mass of benzene (C6H6) = (6 × 12 + 6 × 1) g mol - 1 = 78 g mol - 1 ∴ Number of moles of C6H6 =30/78 mol = 0.3846 mol Molar mass of carbon tetrachloride (CCl4) = 1 × 12 + 4 × 355 = 154 g mol - 1 ∴ Number of moles of CCl4 = 70/154 mol = 0.4545 mol Thus, the mole fraction of C6H6 is given as: = 0.3846 / (0.3846 +0.4545) = 0.458