Calculate the molecular formula of a compound whose empirical formula is ${CH}_{2} O$ and vapour density is 30.

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Solution

Step1: Write the given terms:
Empirical formula = ${CH}_{2} O$
Vapor density = 30
Step 2: Find the molecular formula
As we know,
molar mass = 2 × vapour density
= 2 × 30 = 60 gm
Empirical formula mass = 12 + 2 + 16 = 30
Molecular formula = 2 × ( ${CH}_{2} O$ )= $C_{2} H_{4} O_{2}$
Step 3:
Hence, the molecular formula is $C_{2} H_{4} O_{2}$ .

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. The molecular formula of the compound is :

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Calculate the molecular formula of a compound whose empirical formula is CH2O and vapour density is 30.

Step1: Write the given terms:Empirical formula = CH2OVapor density = 30Step 2: Find the molecular formula As we know,molar mass = 2 × vapour density = 2 × 30 = 60 gmEmpirical formula mass = 12 + 2 + 16 = 30Molecular formula = 2 × (CH2O)=C2H4O2Step 3:Hence, the molecular formula is C2H4O2.

Calculate the molecular formula of a compound whose empirical formula is ${CH}_{2} O$ and vapour density is 30.