Calculate the molecular mass of chloroform $(C H C l_{3})$ .

(Atomic masses: C = 12 u; H = 1 u; Cl = 35.5 u)

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Solution

Atomic mass of C = 12 u
Atomic mass of H = 1 u
Atomic mass of Cl = 35.5 u
Therefore, the molecular mass of $(C H C l_{3})$ can be calculated as follows: (1 $\times$ 12) + (1 $\times$ 1) + (3 $\times$ 35.5) = 119.5 u.

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