Calculate the molecular mass of ethanoic acid, $C H_{3} C O O H$ .

(Atomic masses: C = 12 u; H = 1 u; O = 16 u)

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Solution

Ethanoic acid formula is $C H_{3} C O O H$ .
So, its molecular formula will be: C + (H $\times$ 3) + C + O + O + H = 12 + 3 + 12 + 16 + 16 + 1= 60 u.

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The molecular formula of glucose is $C_{6} H_{12} O_{6}$ . Calculate its molecular mass. (Atomic masses: C = 12 u; H = 1 u; O = 16 u)

Calculate the molecular masses of the following:

(a) Hydrogen, $H_{2}$

(b) Oxygen, $O_{2}$

(d) Ammonia, $N H_{3}$

(e) Carbon dioxide, $C O_{2}$

(Atomic masses: H = 1 u, O = 16 u; Cl = 35.5 u; N = 14 u; C = 12 u)

(H N O_{3})

H = 1 U, N = 14 u, O = 16 u

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