Calculate the molecular mass of glucose $(C_{6} H_{12} O_{6})$ molecule.

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Solution

Since the molecular formula of glucose is $C_{6} H_{12} O_{6}$ , it has $6$ atoms of carbon element, $12$ atoms of hydrogen element, and $6$ atoms of oxygen element.

So, molecular weight of $C_{6} H_{12} O_{6} = (6 \times Atomic weight of corbon + (12 \times Atomic weight of hydrogen) + (6 \times Atomic weight of oxygen))$

$M_{C_{6} H_{12} O_{6}} = 6 \times 12.011 + 12 \times 1.008 + 6 \times 16.00$

$M_{C_{6} H_{12} O_{6}} = 180.162 u$

$Final Answer :$ The molecular mass of glucose $(C_{6} H_{12} O_{6})$ molecule is $180 u .$

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The molecular formula of glucose is $C_{6} H_{12} O_{6}$ . Calculate its molecular mass. (Atomic masses: C = 12 u; H = 1 u; O = 16 u)

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