Question

Calculate the Molecular Mass of $\mathrm{Sucrose}(\mathrm{Table}\mathrm{Sugar}){\mathrm{C}}_{12}{\mathrm{H}}_{22}{\mathrm{O}}_{11}$.

Answer 1

The Atomic Mass of $\mathrm{Carbon}\left(\mathrm{C}\right)$ = $12$.

The Atomic Mass of $\mathrm{Hydrogen}\left(\mathrm{H}\right)$ = $1$.

The Atomic Mass of $\mathrm{Oxygen}\left(\mathrm{O}\right)$ = $16$.

Molecular Mass of $\mathrm{Sucrose}(\mathrm{Table}\mathrm{Sugar}){\mathrm{C}}_{12}{\mathrm{H}}_{22}{\mathrm{O}}_{11}$ = $12\times$(The Atomic Mass of $\mathrm{Carbon}\left(\mathrm{C}\right)$) $+$ $22\times$(The Atomic Mass of $\mathrm{Hydrogen}\left(\mathrm{H}\right)$) $+$ $11\times$(The Atomic Mass of $\mathrm{Oxygen}\left(\mathrm{O}\right)$).

Molecular Mass of $\mathrm{Sucrose}(\mathrm{Table}\mathrm{Sugar}){\mathrm{C}}_{12}{\mathrm{H}}_{22}{\mathrm{O}}_{11}$ = $12\times 12+22\times 1+11\times 16$.

Hence, Molecular Mass of $\mathrm{Sucrose}(\mathrm{Table}\mathrm{Sugar}){\mathrm{C}}_{12}{\mathrm{H}}_{22}{\mathrm{O}}_{11}$) = $342\mathrm{g}/\mathrm{mol}$.