Calculate the molecular mass of the lime stone.

C a C O_{2} = 84 g m o l^{- 1}

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C a C O_{3} = 100 g m o l^{- 1}

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C a_{2} C O_{3} = 140 g m o l^{- 1}

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C a C O = 68 g m o l^{- 1}

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Solution

The correct option is B $C a C O_{3} = 100 g m o l^{- 1}$
Formula for lime stone is $C a C O_{3}$ . Molar mass $= 40 + 12 + (3 \times 16) = 100 g m o l^{- 1}$

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In the conversion of lime stone to lime, $C a C O_{3} (s) \to C a O (s) + C a O_{2} (g)$ the values of $Δ H^{\circ}$ and $Δ S^{\circ}$ are $+ 179.1 k J m o l^{- 1}$ ad $160.2 J K^{- 1} m o l^{- 1}$ respectively at $298 K$ and $1 b a r$ . Assuming, $Δ H^{\circ}$ and $Δ S^{\circ}$ do not change with temperature; temperature above which conversion of lime stone to lime will be spontaneous is