Calculate the moles of F eSO 4 in a 1-824 g sample-A- 0-014B- 0-12C- 0-012D- 0-14

The correct option is C 0.012The molar mass of FeSO_4 = (56+32+16 × 4) g/mol nbsp;= 152 g /mol Therefore, 1.824 g of FeSO_4 = 1.824152 = 0.012 mol ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Mole Concept

Calculate the...

Question

Calculate the moles of $F e S O_{4}$ in a 1.824 g sample?

0.14

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.014

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.12

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.012

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 0.012
The molar mass of $F e S O_{4} = (56 + 32 + 16 \times 4) g / m o l = 152 g / m o l$

Therefore, 1.824 g of $F e S O_{4} = \frac{1.824}{152}$
= 0.012 mol

Suggest Corrections

Similar questions

Q. The value of

\frac{3}{25}

is
(a) 1.2
(b) 0.12
(c) 0.012
(d) None of these

Q. Calculate the moles of

F e S O_{4}

in a 1.824 g sample?

Q. Mark (✓) against the correct answer in each of the following:

\frac{3}{25} = ?

(a) 1.2
(b) 0.12
(c) 0.012
(d) none of these

5

moles of a mixture of

F e S O_{4}

and

F e_{2} (S O_{4})_{3}

required

150 m L

1.0 M K M n O_{4}

in acidic medium for the complete neutralisation. Calculate the mole fraction of

F e S O_{4}

in the initial mixture.

5

moles of a mixture of

F e S O_{4}

and

F e_{2} (S O_{4})_{3}

required

150 m L

1.0 M K M n O_{4}

in acidic medium for the complete neutralisation. Calculate the mole fraction of

F e S O_{4}

in the initial mixture.

Join BYJU'S Learning Program

Calculate the moles of FeSO4 in a 1.824 g sample?

The correct option is D 0.012The molar mass of FeSO4=(56+32+16×4) g/mol=152 g/mol Therefore, 1.824 g of FeSO4=1.824152 = 0.012 mol

Calculate the moles of $F e S O_{4}$ in a 1.824 g sample?

The correct option is D 0.012
The molar mass of $F e S O_{4} = (56 + 32 + 16 \times 4) g / m o l = 152 g / m o l$

Therefore, 1.824 g of $F e S O_{4} = \frac{1.824}{152}$
= 0.012 mol