Question

Calculate the n-factor of $S_2{O}_3$ for the following change.
$2N{a}_2{S}_2{O}_3\to N{a}_2{S}_4{O}_6$

• A. 3
• B. 0.5
• C. 2
• D. 1

Answer 1

The correct option is D 1

For the valency factor
$2N{a}_2{S}_2{O}_3\to N{a}_2{S}_4{O}_6$
O.S. of S in reactant side
$\Rightarrow 2+2x+3\times (-2)=0$
$\Rightarrow x=+2$

O.S. of S in product side
$\Rightarrow 2+4x+6\times (-2)=0$
$\Rightarrow x=+2.5$
$\text{valency factor}=\text{number of S atom}\times |O.S{.}_{Product}-O.S{.}_{Reactant}|$
$\text{valency factor}=2\times |+2.5-2|$
$\text{valency factor}=1$
n-factor of $N{a}_2{S}_2{O}_3=\text{number of sulphur atom}\times |O.S{.}_{Product}-O.S{.}_{Reactant}|=2\times 0.5=1$