Calculate the net force on the body shown.

50 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

30 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

70 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 70 N
50 N and 90 N forces are in the same direction. So, they add up to 140 N.

30 N and 40 N are in the same direction. So, they add up to 70 N.

Net force, F = 140 N - 70 N = 70 N.

Suggest Corrections

Similar questions

Which of the following is divisible by 25:

Coefficient of $x^{n}$ in $(^{n} C_{0} +_{1}^{C} x +^{n} C_{2} x^{2} . . . . . .^{n} C_{n} x^{n}) \times (^{n} C_{0} +^{n} C_{1} \times . . . . .^{n} C_{n} x^{n})$ is

Let $S_{1}$ = $^{n} C_{0}$ + $^{n} C_{1}$ + $^{n} C_{2}$ ............. $^{n} C_{n}$ and $S_{2}$ = $^{n} C_{0}$ - $^{n} C_{1}$ + $^{n} C_{2}$ ..............+ $(- 1)^{n}$ $^{n} C_{n}$

Find the value of $\frac{S_{1}}{S_{1} + S_{2}}$

___

Let $S_{1}$ = $^{n} C_{0}$ + $^{n} C_{1}$ + $^{n} C_{2}$ ............. $^{n} C_{n}$ and $S_{2}$ = $^{n} C_{0}$ - $^{n} C_{1}$ + $^{n} C_{2}$ ..............+ $(- 1)^{n}$ $^{n} C_{n}$

Find the value of $\frac{S_{1}}{S_{1} + S_{2}}$ is ___.

Q. In above shown figure, two force X and Y act perpendicular to each other on a body. Calculate the magnitude of the net force on the body.

Join BYJU'S Learning Program

Calculate the net force on the body shown.

The correct option is C 70 N50 N and 90 N forces are in the same direction. So, they add up to 140 N. 30 N and 40 N are in the same direction. So, they add up to 70 N. Net force, F = 140 N - 70 N = 70 N.

The correct option is C 70 N
50 N and 90 N forces are in the same direction. So, they add up to 140 N.

30 N and 40 N are in the same direction. So, they add up to 70 N.

Net force, F = 140 N - 70 N = 70 N.