Question

Calculate the net work done in the following cycle for one mole of an ideal gas in Calorie. Where in process BC, PT = constant. $(R=2calmo{l}^{-1}{K}^{-1})$.

Answer 1

$w_{\text{total}}=w_{AB}+w_{BC}+w_{CA}$
$w_{AB}=0$ (isochoric)
$w_{BC}=\frac{nR\Delta T}{x-1}$ (polytropic PV${}^{\frac{1}{2}}=$ constant) where $x=\frac{1}{2}$
$=\frac{1\times 2\times 100}{-\frac{1}{2}}=-400cal$
$w_{CA}=-nR\Delta T$(isobaric)
$=-1\times 2\times -300=600cal$
$w_{\text{total}}=0-400+600=200cal$