Question

Calculate the no. of atoms in:

a) 0.5 mol atom of nitrogen

b) 0.2 mol molecules of hydrogen

c)3.2 g of sulphur (Z for sulphur=32)

Answer 1

$\left(a\right)$ $0.5$ mol of atom of nitrogen have $=6.022\times {10}^{23}\times 0.5=3.011\times {10}^{23}$

$\left(b\right)$ $0.2$ mol of molecules of hydrogen have $=6.022\times {10}^{23}\times 0.2=11.204\times {10}^{23}$

$\left(c\right)$ $3.2$ $g$ of $0.1$ mol of sulphur have $=6.022\times {10}^{23}\times 0.1=6.022\times {10}^{22}$