Question

Calculate the no of moles present in $2.044\times {10}^{23}$ number of Helium gas ?

Answer 1

$1$ $mole$ of helium gas has $6.023\times {10}^{23}$ molecules

$⟹1$ $mole\to 6.023\times {10}^{23}$ $molecules$

$⟹x\to 2.044\times {10}^{23}$ $molecules$

$⟹x=\frac{2.044\times {10}^{23}}{6.023\times {10}^{23}}=\frac{1}{3}$

No. of moles of $He=0.33$