Calculate the normality of 1.11 gm of $C a C l_{2}$ is dissolved in 250 ml solution.

0.1 N

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0.25 N

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0.08 N

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0.3 N

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Solution

The correct option is C
0.08 N

Normality = $\frac{N o . o f g r a m e q u i v a l e n t s o f s o l u t e}{V o l u m e o f s o l u t i o n (i n l i t r e)}$

equivalent mass = $\frac{M o l e c u l a r M a s s}{V a l e n e c y f a c t o r}$

= $\frac{111}{2}$ [ ${C a}^{+ 0}$ $\to$ ${C a}^{2 +}$ + $2 e -$ ] = 55.5

No of gram equivalents = $\frac{1.11}{55.5}$

$\Rightarrow$ Normality = $\frac{\frac{1.11}{55.5}}{\frac{250}{1000}}$ = 0.08 N

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