Question

Calculate the normality of $250mL$ aqueous solution of $H_2{SO}_4$ having $pH=0.00$:

• A. $0.25N$
• B. $0.50N$
• C. $1N$
• D. $2N$

Answer 1

Answer: (B)

$0.50N$

$pH=-\log \left[H^{+}\right]$

$\log \left[H^{+}\right]=-pH=0.00$

$\left[H^{+}\right]=anti\log \left(0.00\right)$

$\left[H^{+}\right]=1.0M$

$\therefore$ Normality of $250mL$ solution $=\frac{2\times 250}{1000}=0.50N$