Calculate the normality of a solution containing 50 mL of 5 M solution K2Cr2O7 in acidic medium.
A
15 N
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B
30 N
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C
10 N
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D
None of the above
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Solution
The correct option is B 30 N Volume of solution =50 ml
Molarity of the solution = 5 M
In acidic medium, +6Cr2O2−7→+6Cr3+ nf=|3−6|×2=6| ∴Normality=molarity×nf ⇒Normality=5×6=30N