Calculate the Normality of a solution having 15 gm equivalents dissolved in 750 mL solution.

15 N

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20 N

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75 N

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0.2 N

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Solution

The correct option is B 20 N
$N o r m a l i t y = \frac{N u m b e r o f g r a m e q u i v a l e n t s o f s o l u t e}{V o l u m e o f s o l u t i o n (i n l i t r e s)}$
$= \frac{15}{750 \times 10 - 3} (750 m L \to \times 750 * 10^{- 3} L)$ $= 20 N$

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