Calculate the normality of OH -ions in a solution obtained by mixing 0-01 L of a N -10 NaOH solution and 40 mL of a semi normal KOH solution-A- 0-42 NB- 0-35 NC- 0-10 ND- 0-20 N

The correct option is A 0.42 NNumber of gram equivalents of OH^ ions in 0.01 L of a N/10 NaOH solution= 0.001 Number of gram equivalents of OH^ ions in 40 mL ...

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Byju's Answer

Standard XII

Chemistry

Normality

Calculate the...

Question

Calculate the normality of $O H^{-}$ ions in a solution obtained by mixing 0.01 L of a $\frac{N}{10}$ NaOH solution and 40 mL of a semi normal KOH solution.

0.42 N

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0.35 N

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0.10 N

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0.20 N

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Solution

The correct option is A 0.42 N
Number of gram equivalents of $O H^{-}$ ions in 0.01 L of a $\frac{N}{10}$ NaOH solution= 0.001
Number of gram equivalents of $O H^{-}$ ions in 40 mL of a semi normal KOH= 0.5 $\times$ 0.04= 0.02
Total gram quivalents of $O H^{-}$ ions= 0.021
$N = \frac{0.021}{0.050} = 0.42$ N

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Calculate the normality of OH− ions in a solution obtained by mixing 0.01 L of a N10 NaOH solution and 40 mL of a semi normal KOH solution.

The correct option is A 0.42 NNumber of gram equivalents of OH− ions in 0.01 L of a N10 NaOH solution= 0.001 Number of gram equivalents of OH− ions in 40 mL of a semi normal KOH= 0.5×0.04= 0.02 Total gram quivalents of OH− ions= 0.021 N=0.0210.050=0.42 N

Calculate the normality of $O H^{-}$ ions in a solution obtained by mixing 0.01 L of a $\frac{N}{10}$ NaOH solution and 40 mL of a semi normal KOH solution.