Question

calculate the number of Aluminium ions present in 0.051 grams of Aluminium oxide atomic mass of aluminum is equal to 27n

Answer 1

Dear student ,
Molar mass of Al₂O₃ = 102 gm /mol
Number of moles of Al₂O₃ = 0.051 / 102 = 5 x 10^-4 moles
number of moles of Al ions = 2 x 5 x 10^-4 = 10^-3 moles
Number of Al ions = 6.02 x 10²³ x 10^-3 = 6.02 x 10²⁰
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