Calculate the number of atoms in 52 amu of Helium.

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Solution

Atomic mass of Helium is 4 amu.
1 atom of He = 4 amu
4 amu = 1 atom of He
1 amu $= \frac{1}{4}$ atoms of He
52 amu $= {[\frac{1}{4}] \times 52}$ atoms of He
= 13 atoms of He

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Similar questions

Calculate the number of atoms in each of the following :
(a) 52 moles of He,
(b) 52 Amu of He,
(c) 52 g Of He.

4

2

= 1.00893 a m u

= 1.00814 a m u

H e = 4.0039 a m u

Number of atoms present in $52 g$ of helium is:
$(N_{A}$ is Avogadro’s constant, Gram atomic mass of helium is $4 g)$

Calculate the number of atoms in 52u of He

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