Question

Calculate the number of atoms in each of the following
0.5 mol of atoms of Nitrogen.
0.2 mol of molecules of Nitrogen.
3.2 g of Sulphur.

Answer 1

$0.5$ moles of atoms of nitrogen

$1mole\to V_0$

$0.5\to 0.5\times 6.023\times {10}^{23}atoms$

1 mole cule of $N_2-2atom$

$0.2mol$ molecule $=2\times 0.2\times No$

$=0.4$ No atom

3.2 gm Sulphur

32gm Sulphur $\to$ No atom

$3.2\to \frac{V_0}{10}$ atom

$V_0=6.023\times {10}^{23}$