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Mole Concept and Avogadro's Number

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Question

Calculate the number of atoms of $C$ and $O$ in $72.5$ g isopropanol, $C H_{3} O H$ (molar mass $60$ ).

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Solution

1 mole of $C H_{3} O H$ contains 1 atom of O and 1 atom of c
moles of $C H_{3} O H$ = $\frac{72.5}{60}$ =1.21 moles
Therefore, Number of atoms of C =1.21 atoms
and number of atoms of O= 1.21 atoms

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