Calculate the number of atoms present in $7.1 g$ of chlorine.

0.2 N_{A}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.3 N_{A}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.4 N_{A}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.5 N_{A}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0.2 N_{A}$
Given that

Mass of $C l_{2}, W = 7.1 g$

Molar mass of $C l_{2}, M = 71 g / m o l$

Number of moles $x, = \frac{W}{M} = \frac{7.1 g}{70 g / m o l}$
$= 0.1 m o l$

Each $C l_{2}$ molecule contain $2$ atoms.

$∴$ Number of $C l_{2}$ atom , $N = 2 \times n \times N_{A}$

$= 2 \times 0.1 \times N_{A}$

$= 0.2 N_{A}$

Hence, te correct option is $A$

Suggest Corrections

Similar questions

Calculate the number of molecules and the number of atoms present in 11.2L of Oxygen at N.T.P.

C l_{2}

C a (O H)_{2}

2 C a (O H)_{2} + 2 C l_{2} \to C a (O C l)_{2} + C a C l_{2} + 2 H_{2} O

C a (O C l)_{2}

0.5

C l^{-}

C a C l_{2}

Join BYJU'S Learning Program