Calculate the number of electrons lost or gained the changes:
$C r I_{3} + H_{2} O_{2} + O H^{-} \to C r O_{4}^{- 2} + I O_{4}^{-} + H_{2} O$

Open in App

Solution

$C r I_{3} + H_{2} O_{2} + O H^{-} \to C r O_{4}^{- 2} + I O_{4}^{-} + H_{2} O$
$C r + 3 \to + 6$
lost electrons $= 3$

Suggest Corrections

Similar questions

P b (N_{3})_{2} + C r_{2} O_{7}^{- 2} \to P b_{3} O_{4} + N O_{3}^{-} + C r^{+ 3}

F e (C N)_{6}^{- 4} + C r_{2} O_{7}^{- 2} \to F e^{+ 3} + C_{2} O_{4}^{- 2} + N O_{2}^{-} + C r^{+ 3}

B a C l_{2} + N a_{2} S O_{4} \to B a S O_{4} + 2 N a C l

F e (C N)_{6}^{- 4} + M n O_{4}^{-} \to F e^{+ 3} + C O_{2} + N O_{3}^{-} + M n^{+ 2}

3 I_{2} + 6 N a O H \to N a I O_{3} + 5 N a I + 3 H_{2} O

Join BYJU'S Learning Program