Calculate the number of electrons lost or gained the changes.
$F e (C N)_{6}^{- 4} + M n O_{4}^{-} \to F e^{+ 3} + C O_{2} + N O_{3}^{-} + M n^{+ 2}$

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Solution

$F e (C N)_{6}^{- 4} + M n O_{4}^{-} \to F e^{+ 3} + C O_{2} + N O_{3}^{-} + M n^{+ 2}$
$M n$ from $+ 7 \to + 2$
Hence gain electrons $= 7 - 2 = 5$

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