Calculate the number of electrons lost or gained the changes:
$P b (N_{3})_{2} + C r_{2} O_{7}^{- 2} \to P b_{3} O_{4} + N O_{3}^{-} + C r^{+ 3}$

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Solution

$P b (N_{3})_{2} + C r_{2} O_{7}^{- 2} \to P b_{3} O_{4} + N O_{3}^{-} + C r^{+ 3}$
The oxidation state of Cr changes from +7 to +3 per atom
and there are 2 atoms of the Cr.
Thus total electron gained by the Cr=2x4=8

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